A Treatise on the Theory of Screws
Forfatter: Sir Robert Stawell Ball
År: 1900
Forlag: The University Press
Sted: Cambride
Sider: 544
UDK: 531.1
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84] the principal screws of inertia. 73
so that every pair of them are conjugate screws of inertia (§ 81). Let /?,,&('„
be (6 — /l) screws defining the reciprocal screw system. Let be any
screw belonging to P. Then in the choice of we have n — 1 arbitrary
quantities. Let P be any impulsive screw corresponding to yl, as an instan-
taneous screw. Choose A., reciprocal to ZX1 ... 56-»> then and A2 are
conjugate screws, and in the choice of the latter we have n — 2 arbitrary
quantities. Let Z2 be any impulsive screw corresponding to A2 as an instan-
taneous screw. Choose A3 reciprocal to P, I2, Ip, ... lp-n, and proceed thus
until JLn has been attained, then each pair of the group .J1; &c. An are
conjugate screws of inertia. The number of quantities which remain
arbitrary in the choice of such a group amount to
„ , n(n— 1)
11 — 1 + TO — 2 + ... + 1 =-a--,
or exactly half the total number of arbitrary constants disposable in the
selection of any n screws from a system of the nth order.
84. Principal Screws of Inertia.
We have now to prove the important theorem in Dynamics which affirms
the existence of n principal Screws of Inertia in a rigid body with n degrees
of freedom.
The proof that we shall give is, for the sake of convenience, enunciated
with respect to the freedom of the third order, but the same method applies
to each of the other degrees of freedom.
Let 0 be one of the principal screws of inertia, then an impulsive wrench
on 0 must make the body commence to twist about 0. In the most general
case when the body is submitted to constraint, the impulsive wrench on 0 will
of course be compounded with the reaction on some screw Å. of the reciprocal
system. The result will be to produce the impulsive wrench which would,
if the body had been free, have generated an instantaneous twist velocity
about 0.
We thus have the following equations (§ 80) where x and y are unknown:
p10l = x02 + yXi,
p20'i — x02 + yX2,
pPP = »P, + yK-
Let a be one of the screws of the three-system in question. Then since X
must be reciprocal to a we have by multiplying these equations respectively
by p^i,... p^6 anå adding,
+ •••+ PfaO» = xpiuA 4- xp2a202 + ... + xpsae0e.