Steam:
Its Generation and Use
År: 1889
Forlag: Press of the "American Art Printer"
Sted: New York
Sider: 120
UDK: TB. Gl. 621.181 Bab
With Catalogue of the Manufacturers.of The Babcock & Wilcox Co.
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■4
FLOW OF STEAM THROUGH PIPES.
The approximate weight of any fluid which
will flow in one minute through any given pipe
with a given head or pressure may be found by
the following formula:
W — 300 /i
/^ (A - A) d’-
in which //z= weight in pounds avoirdupois,
d — diameter in inches, D — density or weight
per cubic foot; pr the initial pressure, p.> pressure
at end of pipe, and L — the length in feet.
The following table gives, approximately, the
weight of steam per minute which will flow from
various initial pressures, with one pound loss of
pressure through straight smooth pipes, each
having a length of 240 times its own diameter.
For sizes of pipe below 6-inch, the flow is cal-
culated from the actual areas of “standard”
pipe of such nominal diameters.
The resistance at an elbow is equal to % that
of a globe valve. These equivalents—for open-
ing, for elbows, and for valves,— must be added
in each instance to the actual length of pipe.
Thus a 4-in. pipe, 120 diameters (40 feet) long,
with a globe valve and three elbows, would be
equivalent to 120 + 60 + 60 + (3 X 40) = 360
diameters long ; and 360 -s- 240 = It would
therefore have lbs. loss of pressure at the
flow given in the table, or deliver (1 -s- -j/i^
= .816), 81.6 per cent, of the steam with the same
(1 lb.) loss of pressure.
FLOW OF STEAM FROM A GIVEN ORIFICE.
Steam of any pressure flowing through an
opening into any other pressure, less than three-
fifths of the initial, has practically a constant
velocity, 888 feet per second, or a little over ten
miles per minute; hence the amount discharged
in pounds is proportionate to the weight or dens-
ity of the steam. To ascertain the pounds,
TABLE OF FLOW OF STEAM THROUGH PIPES.
c
Diameter of Pipe in inches. Length of each 240 diameters.
tue cr □ V) u. % 2 3 4 . 5 6 8 ’° 12 '5 ■8
Initi by lbs. p Weight of Steam per minute in pounds, with one pound loss of pressure.
1 1.16 2.07 5-7 10.27 T5-45 25-38 46-85 77-3 115-9 211.4 341-i 502.4 804 1177
10 1 -44 2-57 7-1 12.72 19.15 3T-45 58-05 95 8 143.6 262.0 422-7 622.5 996 1458
20 1.70 3-02 8.3 14.94 22.49 36-94 68.20 112.6 168.7 307.8 496-5 731-3 1170 1713
30 i.91 3-4° 9-4 16.84 25-35 41-63 76.84 126.9 190.1 30 8 559-5 824. i 1318 1930
40 2.10 3-74 i". > 18.51 27.87 45-77 84-49 139-5 209.0 38i-3 615-3 906.0 ’45° 2122
50 2.27 4-°4 11.2 2O.OI 30.13 49.48 9I-34 150.8 226.0 412.2 665.0 979-5 1567 2294
60 2-43 4-32 II.9 21.38 32.19 52-87 97.60 t6i . i 24I-5 440-5 710.6 1046.7 1675 2451
70 2.57 4-58 12.6 22.65 34-1° 56.00 103.37 170.7 255-8 466.5 752-7 1108.5 1774 2596
80 2.71 4.82 *3-3 23-82 35.87 58.91 108.74 179-5 269.0 490-7 791.7 ii66.i 1866 2731
90 2.83 5'°4 J3-9 24.92 37 -52 61.62 113-74 187.8 281.4 513-3 828. i 1219.8 1951 2856
100 z-95 5-25 14-5 25.96 39-07 64.18 118.47 195-6 293.1 534-6 862.6 1270.I 2032 2975
170 3.16 5-63 15.5 27.85 4I*93 68.87 I27.12 209.9 3J4'5 573-7 925.6 J3^3-3 2181 3193
150 3-45 6.14 17.0 3° -37 45.72 75-°9 138.61 228.8 343-° 625.5 1009.2 1486.5 2378 3481
For horse-power, multiply the figures in the
table by 2. For any other loss of pressure, mul-
tiply by the square root of the given loss. For
any other length of pipe, divide 240 by the given
length expressed in diameters, and multiply the
figures in the table by the square root of this
quotient, which will give the flow for 1 lb. loss of
pressure. Conversely dividing the given length
by 240 will give the loss of pressure for the How
given in the table.
The loss of head due to getting up the velocity,
to the friction of the steam entering the pipe, and
passing elbows and valves, will reduce the flow
given in the tables. The resistance at the open-
ing, and that at a globe valve, are each about the
same as that fora length of pipe equal to 114
diameters divided by a number represented by
t (3.6 -i- diameter). For the sizes of pipes
given in the table, these corresponding lengths are :
I 1 I I 2 l 2^ I 3 I 4 I 5 I 6 I 8 I 10 I X2 I 15 I i!
20 I 25 I 34 I 41 I 47 I 52 I 60 I 66 I 71 I 79 I 84 I 88 i 92 I 9^
avoirdupois, discharged per minute, multiply
the area of opening in inches, by 370 times the
weight per cubic foot of the steam. (See p. 49 .)
Or the quantity discharged, per minute, may
be approximately found by Rankine’s formula :
W — 6 a p -r- 7 in which W— weight in pounds,
a=area, in square inches, and p — absolute press-
ure. The theoretical flow requires to be mul-
tiplied by >{1 = 0.93, for a short pipe, or 0.63 for a
thin opening, as in a plate, or a safety valve.
Where the steam flows into a pressure more
than the pressure in the boiler:
IF— 1.9 a k 3/ (/> — 8) b; in which 8 = differ-
ence in pressure between the two sides, in pounds
per square inch, and a, p and k as above.
To reduce to horse-power, multiply by 2.
Where a given horse-power is required to flow
through a given opening, to determine the nec-
essary difference in pressure :
8 =
2
H.P.2
i4«a k
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