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2o6
HARBOUR ENGINEERING.
buoyancy, it is only necessary to draw, perpendicular to the
a line from the given point B2 on the buoyancy curve until it
axis QK.
Its position may be located algebraically, thus:—
' B1M2=M2C + CB1
= M2C + y.
Now, the triangles CB2M2 and RFO are similar, their sides
tively at right angles to one another.
Therefore
water surface,
intersects the
being respec-
M2C =!g.CB2
L
SA*’
and
But
BlM2=2^a:+y’
AL , A2
a:- and y = —-,
6D J 6D
whence substituting
1.2 A2
1 2 12D 611
T 2
So when A is zero in the initial position, B^l^ ^^j and when A = RH,
BjM2=—+—.
1 2 12D 6
Tire range of position of the inetacentre is accordingly within a length
upon the axis QK, and, similarly, within a length ^ upon the axis RT.
A much simpler method, however, may be devised for obtaining the
position of the metacentre by geometrical construction.
It will be observed that the equation of the parabola,
60
y L2 ’
is satisfied by the values «=—-, y=—; that is to say, the curve passes
through the points G and P, which are the uppermost corners of the pontoon.
Knowing also the vertex, Bp of the curve, it is a very easy matter to con-
struct, by auy of the recognised methods, the parabolic arc GB^,* the portion
of which, aß lying between the semi-diagonals HO and ON, constitutes a part
of the buoyancy curve (fig. 180).
Now, for any assigned water-line FS, take the chord fs on this line which
* Vide construction, fig. 187, p. 213.