283
OF ENGINEERING KOKMUL2E.
Pumping Engines.
G = Number of gallons to be raised in 24 hours.
~ Number of cube feet raised in 24 hours.
— Height in feet to which the water is to be
raised.
H P = Actual horse-power required
__ Gr X Å F X h
1 ~ 4752000 Or 762088 '
20 per cent, must be added to overcome a
fiction, &c., and 50 or 60 per cent, more is usually
allowed for contingencies, making a total of 70 or
80 per cent, additional power.
To find the Diameter of a Single-acting Pump.
G
F
N
D
F _________
G = -034 D2 LN.
D =
L = Length of stroke in feet.
Number of galls, to be delivered per minute.
Number of cub. ft. to be delivered per minute.
A umber of strokes per minute.
Diameter of pump in inches
•00545 D2 LN.
Note.—These formulae
give the net diameter of
the pump-plunger; it is
usual to increase the area
of the plunger |th, to
allow for leakage, &c.
G
•034 LN
F
D =
V -00545 LN
Useful Numbers foe Pumps.
D = Diameter of pump in inches.
S = Stroke of pump in inches.
D.2 S x '7854 = cubic inches
D.2 S x -002833 = gallons.
IV S x • 0004545 = cubic feet.
I*.2 S x '02833 = lbs. fresh water.